2022朝阳市中考英语
X.书面表达(本题共1小题,满分15分)
自从“双减”政策实施以来,我们学生有更多的空闲时间参与文娱、体育、艺术等方面的课外活动,这些活动为我们的生活增添了生机和活力。请以“After-school Activities Make My Life Colorful”为题,写一篇英语短文来介绍你参与的课外活动。
内容:
1. 介绍你所参与的1至2项关于文娱、体育或艺术方面的课外活动;
2.谈一谈课外活动给你带来的收获及感受。
要求:
1.文中不得出现真实姓名校名或地名;
2.语言通顺,意思连贯,书写工整;
3.词数在80词左右,短文开头已给出,不计入总词数。
After- school Activities Make My Life Colorful
Nowadays, we have more free time to take part in after -school activities.________________
_______________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
2022年朝阳市初中学业水平考试
英语试题参考答案
X.书面表达(参考范文)
Nowadays, after-school activities are becoming more and more popular. There are many different kinds of activities, for example, arts and sports. I joined a volleyball club last year. I am used to playing volleyball after school.
In the volleyball club, I’ ve made lots of friends. We often play volleyball after school. Whether it is hot or cold, we never stop playing it. I feel happy while playing volleyball. And it is also a good way to relax myself. I think I will continue to play volleyball after school in the future.
All in all, after-school activities make my life more colorful and meaningful.
▍来自:张老师教英语
X.书面表达(本题共1小题,满分15分)
自从“双减”政策实施以来,我们学生有更多的空闲时间参与文娱、体育、艺术等方面的课外活动,这些活动为我们的生活增添了生机和活力。请以“After-school Activities Make My Life Colorful”为题,写一篇英语短文来介绍你参与的课外活动。
内容:
1. 介绍你所参与的1至2项关于文娱、体育或艺术方面的课外活动;
2.谈一谈课外活动给你带来的收获及感受。
要求:
1.文中不得出现真实姓名校名或地名;
2.语言通顺,意思连贯,书写工整;
3.词数在80词左右,短文开头已给出,不计入总词数。
After- school Activities Make My Life Colorful
Nowadays, we have more free time to take part in after -school activities.________________
_______________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
2022年朝阳市初中学业水平考试
英语试题参考答案
X.书面表达(参考范文)
Nowadays, after-school activities are becoming more and more popular. There are many different kinds of activities, for example, arts and sports. I joined a volleyball club last year. I am used to playing volleyball after school.
In the volleyball club, I’ ve made lots of friends. We often play volleyball after school. Whether it is hot or cold, we never stop playing it. I feel happy while playing volleyball. And it is also a good way to relax myself. I think I will continue to play volleyball after school in the future.
All in all, after-school activities make my life more colorful and meaningful.
▍来自:张老师教英语
#MY杂货铺[超话]##nct西珍妮[超话]#
出aespa nct dream闪卡全新未拆
aespa girls闪卡 柚冬70r 吉宁65r
柚x3 冬x2 吉x2 宁x2
nct dream 梦想洗衣房闪卡 娜诺65r
娜x1 诺x3
12月底回国 包国际不包国内 不需要提确
tag:aespa nct nct dream 闪卡 girls 梦想洗衣房 柳智敏 金玟庭 宁艺卓 内永绘里 罗渽民 李帝努 柚 冬 宁 吉赛尔 娜 诺 Karina winter ningning Gisele jaemin jeno
出aespa nct dream闪卡全新未拆
aespa girls闪卡 柚冬70r 吉宁65r
柚x3 冬x2 吉x2 宁x2
nct dream 梦想洗衣房闪卡 娜诺65r
娜x1 诺x3
12月底回国 包国际不包国内 不需要提确
tag:aespa nct nct dream 闪卡 girls 梦想洗衣房 柳智敏 金玟庭 宁艺卓 内永绘里 罗渽民 李帝努 柚 冬 宁 吉赛尔 娜 诺 Karina winter ningning Gisele jaemin jeno
【群友提问】
如图,已知抛物线y^2=2x,过点P(1,0)和Q(3,0)分别作斜率大于0的两平行直线,交抛物线于A,B和C,D,连接AD交x轴于点M(3/2,0),则直线AB的斜率是().
A1 B√2 C√3 D2
【大罕解答】
解1:用排除法.由条件知,
|PM|∶|MQ|=|y(A)|∶|y(B)|=1∶3,因此3y(A)=- y(B),
若选A,把直线AB、CD方程分别与抛物线方程联立,即
由y=x-1,且y^2=2x,⇒ y(A)= 1-√3;
由y=x-3,且y^2=2x,⇒ y(B)=1+√7,显然不符,排除A.
同理,选B,C均不符.
而若选D,由y=2x-2,且y^2=2x,⇒ y(A)= -1;
由y=2x-6,且y^2=2x,⇒ y(B)=3,符合要求.至此可选D.
解2:常规方法.
设AB:x=my+1,CD;x=my+3,
将AB、CD方程分别与抛物线方程联立,解得
y(A)=m-√(m^2+2),y(B)=m+√(m^2+6),
由条件知,|PM|∶|MQ|=|y(A)|∶|y(B)|=1∶3,
∴3y(A)=- y(B),
即3[m-√(m^2+2)]=-[m+√(m^2+6)],
解得m=1/2,∴直线AB的斜率是2,选D.
【说明】选择题尽量不要做成解答题,故解法1是可取的.本题的解法2有点麻烦,考查快速准确的计算能力.
2022-11-8
#高中数学##高考#
如图,已知抛物线y^2=2x,过点P(1,0)和Q(3,0)分别作斜率大于0的两平行直线,交抛物线于A,B和C,D,连接AD交x轴于点M(3/2,0),则直线AB的斜率是().
A1 B√2 C√3 D2
【大罕解答】
解1:用排除法.由条件知,
|PM|∶|MQ|=|y(A)|∶|y(B)|=1∶3,因此3y(A)=- y(B),
若选A,把直线AB、CD方程分别与抛物线方程联立,即
由y=x-1,且y^2=2x,⇒ y(A)= 1-√3;
由y=x-3,且y^2=2x,⇒ y(B)=1+√7,显然不符,排除A.
同理,选B,C均不符.
而若选D,由y=2x-2,且y^2=2x,⇒ y(A)= -1;
由y=2x-6,且y^2=2x,⇒ y(B)=3,符合要求.至此可选D.
解2:常规方法.
设AB:x=my+1,CD;x=my+3,
将AB、CD方程分别与抛物线方程联立,解得
y(A)=m-√(m^2+2),y(B)=m+√(m^2+6),
由条件知,|PM|∶|MQ|=|y(A)|∶|y(B)|=1∶3,
∴3y(A)=- y(B),
即3[m-√(m^2+2)]=-[m+√(m^2+6)],
解得m=1/2,∴直线AB的斜率是2,选D.
【说明】选择题尽量不要做成解答题,故解法1是可取的.本题的解法2有点麻烦,考查快速准确的计算能力.
2022-11-8
#高中数学##高考#
✋热门推荐